For example, you want to study the productivity of various types of machinery and the satisfaction of operators in their use (as with a number from 1 to 10). These are the values:
Productivity: 5, 7, 9, 9, 8, 6, 4, 8, 7, 7
Satisfaction: 6, 7, 4, 4, 8, 7, 3, 9, 5, 8
Satisfaction: 6, 7, 4, 4, 8, 7, 3, 9, 5, 8
Begin to use first the Spearman's rank correlation coefficient:
a <- c(5, 7, 9, 9, 8, 6, 4, 8, 7, 7)
b <- c(6, 7, 4, 4, 8, 7, 3, 9, 5, 8)
cor.test(a, b, method="spearman")
Spearman's rank correlation rho
data: a and b
S = 145.9805, p-value = 0.7512
alternative hypothesis: true rho is not equal to 0
sample estimates:
rho
0.1152698
The statistical test gives us as a result rho = 0.115, which indicates a low correlation (not parametric) between the two sets of values.
The p-value > 0.05 allows us to accept the value of rho calculated, being statistically significant.
Now we check the same data with the Kendall tau rank correlation coefficient:
a <- c(5, 7, 9, 9, 8, 6, 4, 8, 7, 7)
b <- c(6, 7, 4, 4, 8, 7, 3, 9, 5, 8)
cor.test(a, b, method="kendall")
Kendall's rank correlation tau
data: a and b
z = 0.5555, p-value = 0.5786
alternative hypothesis: true tau is not equal to 0
sample estimates:
tau
0.146385
Even with the Kendall test, the correlation is very low (tau = 0.146), and significant (p-value > 0.05).
"The p-value > 0.05 allows us to accept the value of rho calculated, being statistically significant."
ReplyDeleteNooooo....
Since p > 0.05, the sample rho is NOT statistically significant. This means you do not have sufficiently strong evidence to reject the null hypothesis (so it seems that the true rho could be zero... or at least, you haven't found convincing evidence that it isn't)
I completely agree with the above point. Please change and the statement. you cannot reject null at such a high p-value.
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